2(1.07^2x+1)=15

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Solution for 2(1.07^2x+1)=15 equation: 



2(1.07^2x+1)=15

We move all terms to the left:

2(1.07^2x+1)-(15)=0

We multiply parentheses

2x+2-15=0

We add all the numbers together, and all the variables

2x-13=0

We move all terms containing x to the left, all other terms to the right

2x=13

x=13/2

x=6+1/2

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